LC1143 - Longest Common Subsequence

Problem

Given two strings text1 and text2, return the length of their longest common subsequence. If there is no common subsequence, return 0.

A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.

  • For example, "ace" is a subsequence of "abcde".

A common subsequence of two strings is a subsequence that is common to both strings.

Example

Input: text1 = "abcde", text2 = "ace"

Output: 3

Explanation: The longest common subsequence is "ace" and its length is 3.

Solution

2D Dynamic Programming

Lay the words against each other on a 2D grid and fill in values of the path. Time and space complexity is O(mā‹…n)O(m\cdot n), where mm is the length of text1 and nn is the length of text2.

def longestCommonSubsequence(self, text1: str, text2: str) -> int:
	# Allocate empty matrix
	arr = [[0 for _ in range(len(text2) + 1)] for _ in range(len(text1) + 1)]
	
	for i in range(len(text1)-1, -1, -1):
		for j in range(len(text2)-1, -1, -1):
			if text1[i] == text2[j]:
				arr[i][j] = 1 + arr[i+1][j+1]
			else:
				arr[i][j] = max(arr[i][j+1], arr[i+1][j])
	
	return arr[0][0]

Last updated